NEW DELHI: In a remarkable display of batting prowess, star Indian batters
Rohit Sharma
and
Rinku Singh
etched their names in T20I history by matching the record for the highest number of runs scored off a single over.
The final five overs of the match witnessed a spectacular display of power-hitting as India accumulated a staggering 103 runs. Rohit and the left-handed Rinku in particular stole the show by smashing an incredible 36 runs off
Afghanistan
's
Karim Janat
's final over of the innings, which included a six off a no-ball.
Rohit opened the over with a stunning four, and followed it up with consecutives sixes off a no-ball and on a free hit. Rohit then took a single off the third ball of the over, handing the baton to Rinku, who hit three humongous back-to-back sixes off the final three balls.
The duo equalled the record set by
Yuvraj Singh
and
Kieron Pollard
. Both Yuvraj and Pollard had previously achieved this remarkable milestone by hitting six sixes in a single over against England and Sri Lanka, respectively.
Despite a shaky start that saw India struggling at 22-4, with star batsman
Virat Kohli
dismissed for a first-ball duck after choosing to bat first in Bengaluru, Rohit emerged as the saviour.
The dynamic opener not only surpassed the records of Australia's
Glenn Maxwell
and
Suryakumar Yadav
, each with four T20I centuries, but also played a breathtaking innings.
Rohit's spectacular knock of 121 runs off 69 balls, supported by an unbeaten 190-run partnership with Rinku Singh, turned the tide, rescuing India from a precarious position.
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